consider this systems of equations 2/3 x +3/5 y =12 5/2 y - 3x=6 the expression that gives the value of x is... the solution for the systems of equations...
Do you know how to solve simultaneous equations?
no
A) 2/3 x +3/5 y =12 B) -3x +5/2 y =6 One way is to solve for x in one equation
I don't get it
B) -3x = -5/2 y + 6 We divide both sides by -3 x = 5/6 y -2
options the expression that gives the value of x is... (5A/3)+(2B/5), (3A/5)-(5B/2), (5A/2)+(3B/5), (5A/3)-(2B/5), (3A/2) + (B/3)
mcfizzy STOP! What is that attachment?
the solution to the systems of equations is (1118/47, 396/47) (33/13, 50/13) (99/13, 150/13) (8,12)
@UsukiDoll what's wrong?
I've seen this poster (mcfizzy) posting an attachment that could be malicious. I've sent a report.
okay, I probably shouldn't click on the attachment then. I'll send a report too.
yeah.. under his profile all of his questions answered has spam with that attachment. everyone please report this.
I could use help with this problem, I'm still very confused
x = 99/13 y = 150/13
@wolf1728 is there to help. I have to warn everyone else about this issue as this is serious and against terms and conditions.
okay thank you
@wolf1728 I also need the expression that gives the value of x
Kaelyn - you do not know how to solve these so why do you need the expression for value of x ?
because the question asks me to find the expression that finds the value of x, I don't want you to give me the answer just help me find the right one
I think you should find someone else to help. I'm quitting for the moment.
okay thank you for your help
please help
May I try?
go for it @waterineyes as long as it's not a direct answer
go ahead @waterineyes
and @UsukiDoll I agree don't give the answer to me just help me find the answer myself
Okay, don't let our interaction stop anywhere, just reply if you know or not, just be with me...
okay
\[\frac{ 2 }{ 3 }x+\frac{ 3 }{ 4 }y=12\]\[\frac{ 5 }{ 2}y-3x=6\]frm equation 2,\[\frac{ 5 }{ 2 }y=6+3x\]\[y=\frac{ 2(6+3x) }{ 5 }\]now sub y=2(6+3x)/5 in eq 1 \[\frac{ 2 }{ 3 }x+\frac{ 3 }{ 4 }(\frac{ 2(6+3x) }{ 5 })=12\]simplify and solve for x we get \[\frac{ 2 }{ 3 }x+\frac{ 36+18x }{ 20 }=12\]\[\frac{ 40x +108+54x}{ 60 }=12\]\[\frac{ 94x+108 }{ 60 }=12\]multiply both side of the equation we get..\[94x+108=720\]\[94x=720-108\]\[x=612/94\]\[x=6.510638\]...so y =...\[y=\frac{ 2(6+3(6.510638)) }{ 5 }\]\[y=10.21276\]..
okay understanding so far
-_- *throws a water bottle @waterineyes
Both our equations are in fraction form, we should simplify them to make a good looking equation first... Do you know how to take LCM?
Hell, my net stopped working.. :(
Yes I know how to take LCM
Like in first equation, 15 is the LCM, so you can multiply whole equation by 15...
@LynFran I am afraid you are right everywhere, but you have taken wrong fraction in very first equation,, 3/5 is good, not 3/4.. if I am not blind then.. :P Your method is good.. :)
if we find our y and x, keep it in fraction form. ... decimals are a pain to deal with T_T
*throws a canteen at @waterineyes
Guys lets not throw things...
o i see im sleepy lol @waterineyes goodnight u guys
Goodnight @LynFran
\(10x + 9y = 180\) --- 1 This you got?
what is that ?
sigh....... the second equation is easier to deal with 2/3 x +3/5 y =12 5/2 y - 3x=6 \[\frac{2}{3}x+\frac{3}{5}y=12\] \[\frac{5}{2}y-3x=6\] so multiply 2 throughout the entire second equation \[\frac{5}{2}y-3x=6\]
And this way your second equation becomes: \(5y - 6x = 12\) --------- 2
uh huh
@Kaelyn78 are you getting how I formed these two equations?
yes I understand
10x + 9y = 180 5y-6x=12
Thanks.. Again and again I was going above to see these equations, as you are posting in between so things are going above..
you can write the second equation, other way round, x first and then y: \(10x + 9y = 180 \\ -6x + 5y = 12\)
\[[10x + 9y = 180 ] \times 6 = 60x + 45y = 108 \\ [-6x + 5y = 12 ] \times 10 = -60x + 50y = 120\]
I have multiplied the coefficient of x in second equation with first equation and same for second equation.. are you getting this step?
yes I understand
Now you just need to add those equations...
\[\cancel{60x} + 45y = 1080 \\ \cancel{-60x} + 50y = 120 \\ --------- \\95y = 2200\]
Sorry, that is 1080 and not 108...
okay
Getting previous step?
yes I'm getting it
Now find y, by dividing by 95 both the sides..
23?
Wait, I am just double checking it.. Let me take copy and pen too..
It is certainly a wrong...
9 multiplied by 6 is 54 not 45, just keep eyes on what I am doing, I can be wrong anywhere in writing digits. :P
After Multiplying 6 and 10 the equations you will get are: \(60x + 54y = 1080 \\ -60x + 50y = 120\) Form this you will get: \(104y = 2200\)
Kill me.....
1080 + 120 = 1200.. What has happened to me today.. :(
@waterineyes aw sorry I can't help with that
\(104y = 1200\) Now just find y by cancelling out the things..
if it's any consolation I would have gone certifiably insane trying to do this all by myself
thank you
\[y = \frac{1200}{104}\]
gotta reduce that fraction
Do not use calculator, just cancel it out with 8, you will get in fraction..
Now, put the fraction in any one of the equation above to find x...
Found value of y?
\[y=\frac{150}{13}\] 5y-6x=12 plug in y in this equation and solve for x
what are you talking about? I didn't post that.
\[5(\frac{150}{13})-6x=12\]
@Kaelyn78 what you got for y? You break the interaction?? :(
Okay, I gotta go now. If any doubt, Doll will tell you, or I will when I login next.. :) Solving these types of equations is really an easy task, just learn the concept, rest is a-jiffy work..
sorry fell asleep
I'm going to bed, thanks everyone, goodnight
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