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Using the graph of f(x) = log2x below, approximate the value of y in the equation 22y = 4.
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2^2y=4
if we take the logarithm with base 2 of your equation, we get: \[\Large \begin{gathered} {2^{2y}} = 4 \hfill \\ \hfill \\ 2y{\log _2}2 = {\log _2}4 \hfill \\ \hfill \\ 2y = {\log _2}4 \hfill \\ \end{gathered} \]
now, using the properties of logarithm in any base, we can write: \[\Large {\log _2}4 = {\log _2}\left( {{2^2}} \right) = 2{\log _2}2\]
so the answer would be 1
yes!
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thank you so much
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