Question

(sinx/(1-cosx)) + (sinx/1+cosx)) = 2 cscx

Answer 1

\[\frac{sinx }{1-cosx}+\frac{sinx }{1+cosx}=\\sinx (\frac{1 }{1-cosx}+\frac{1 }{1+cosx})\\sinx (\frac{1+cosx +1-cosx }{1-\cos^2x})=\\ \frac {2\sin x}{1-\cos^2x}\]
can you go on ?

Answer 2

1-cos^2x=sin^2x
2sinx/sin^2x =2/sinx
2/sinx= 2csc x
I think I get it thanks.