Question

derivative of sin(lnx)

Answer 1

I know derivative of lnx is 1/x

Answer 2

Do you know your chain rule?

Answer 3

I think so! Just dont know where to start

Answer 4

I would assume we do something like 1/u*du/dx

Answer 5

if you have \(y=f[g(x)]\) then:
\(y'=f'[g(x)]g'(x)\)

Answer 6

Ill just get help on chegg

Answer 7

If you look at yours, you have sin(lnx) so, f(x) is sin(x) and g(x) is ln x.

Answer 8

So, what is the derivatve of sin(x)?