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I'll FAN & MEDAL!! Find the sum.
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\[\frac{ -9 }{ mn ^{2} } +\frac{ m ^{2} }{ n }\]
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they're aren't any
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Its ok
M3n-9 over mn2
|dw:1437496363066:dw|
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You need to multiply each side to get a common denominator. The common denominator would be mn^2. Because the first term already has it, the second term need to be multiply by mn on the top and bottom to get a common denominator.|dw:1437496175565:dw|
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