Question

***FAN AND MEDAL***

Answer 1

Sal's Sandwich Shop sells wraps and sandwiches as part of its lunch specials. The profit on every sandwich is $2 and the profit on every wrap is $3. Sal made a profit of $1,470 from lunch specials last month. The equation 2x + 3y = 1,470 represents Sal's profits last month, where x is the number of sandwich lunch specials sold and y is the number of wrap lunch specials sold.

Answer 2

1)Change the equation to slope-intercept form. Identify the slope and y-intercept of the equation. Be sure to show all your work.

Answer 3

2)Describe how you would graph this line using the slope-intercept method. Be sure to write using complete sentences.

Answer 4

@jim_thompson5910 @mathstudent55 HELP!!!

Answer 5

@ganeshie8 help!!!

Answer 6

Yes

Answer 7

did you get #1 started at all?

Answer 8

no

Answer 9

they want you to solve 2x + 3y = 1,470 for y. Do you know how?

Answer 10

let me try

Answer 11

ok tell me what you get

Answer 12

Part a)
2x + 3y = 1,470
3y = -2x + 1470
y = (-2x + 1470 ) / 3
y = -2/3 * x + 1470/3
y = -2/3 * x + 490
slope is -2/3
y intercept is 490

Part b)
Plot the y intercept (0,490) and the x intercept (735,0)
Connect the two intercepts with a straight line

Part c)
f(x) = -2/3 * x + 490
The graph shows the number of wraps sold as a function of the number of sandwiches sold.

Answer 13

x = 735-3y/2

Answer 14

Part e)
2x + 3y = 1593
3y = -2x + 1593
y = -2/3*x + 1593/3
y = -2/3*x + 531

The graphs are similar in that they are parallel .
They are dissimilar in that they have different y intercepts.

Part f)
not enough information given. Directions say 'below is a graph'

Answer 15

@jim_thompson5910

Answer 16

hope that helps :)

Answer 17

are you there? @jim_thompson5910 ???

Answer 18

@Kim21 thank you so much!! for the answers