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Mathematics 12 Online
OpenStudy (anonymous):

4 over 3 minus 2i

OpenStudy (anonymous):

|dw:1437528906007:dw|

OpenStudy (anonymous):

You must multiply both numerator and denominator by the conjugate of 3-2i. Do you know what that is?

OpenStudy (ali2x2):

multiply 4 and 3 what do you get?

OpenStudy (anonymous):

12

OpenStudy (ali2x2):

Good

OpenStudy (ali2x2):

Now 12 is now your new numeratior, (12/3)

OpenStudy (ali2x2):

now divide 12 and 3

OpenStudy (anonymous):

4

OpenStudy (ali2x2):

ok 4/3

OpenStudy (ali2x2):

divide 4 and 3

OpenStudy (anonymous):

1.3333333

OpenStudy (ali2x2):

woops 3 and 4

OpenStudy (ali2x2):

you get 1

OpenStudy (ali2x2):

left

OpenStudy (ali2x2):

no 5 1/3

OpenStudy (anonymous):

i got 0.75

OpenStudy (ali2x2):

you get 5 and 1/3

OpenStudy (ali2x2):

Yes correct

OpenStudy (ali2x2):

5 and 1/3 is your answer

OpenStudy (anonymous):

thats not one of the options

OpenStudy (ali2x2):

what are they

OpenStudy (anonymous):

???? What happened to the imaginary part?

OpenStudy (ali2x2):

he said that wa not one of the options

OpenStudy (ali2x2):

i did it the way with a number I TOTALLY FORGOT THE NAAME XDDDd

OpenStudy (anonymous):

1. 4/ 13 2. 16/13 3.12+8i/13 4.12-8i/13

OpenStudy (anonymous):

You must simplify by multiplying both numerator and denominator by the conjugate of 3-2i, which is 3+2i. So you must calculate\[\frac{ 4 }{ 3-2i }\times \frac{ 3+2i }{ 3+2i }\]Are you able to do that?

OpenStudy (anonymous):

12+8i? over 13?

OpenStudy (ali2x2):

im out im kinda rushing anyway :/

OpenStudy (anonymous):

i dont have to simplify all the way i dont think

OpenStudy (anonymous):

and okay bye ali2x2 thanks for the help

OpenStudy (anonymous):

Excellent. So you've got\[\frac{ 12+18i }{ 13 }\]No more simplification possible. Well done.

OpenStudy (anonymous):

oksy thank you very much

OpenStudy (anonymous):

You're welcome

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