fan medal and testimony help!!!.
What is the solution to the equation 1.2m − 0.8 = −2.0m?
m = 0.25
m = 0.4
m = 1
m = 4
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Mehek (mehek14):
first add 1.2 + 2
OpenStudy (anonymous):
3.2
Mehek (mehek14):
and add 0 + 0.8
OpenStudy (anonymous):
0.8
Mehek (mehek14):
so you have
\(3.2m = 0.8\)
now divide
\(\dfrac{0.8}{3.2}\)
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OpenStudy (anonymous):
0.25
Mehek (mehek14):
\(m=0.25\)
OpenStudy (anonymous):
thanks can you help with a couple more
Mehek (mehek14):
sure
OpenStudy (anonymous):
thanks your great!
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Mehek (mehek14):
^_^
OpenStudy (anonymous):
Which statement is true about the equation fraction 3 over 4z − fraction 1 over 4z + 1 = fraction 2 over 4z + 1?
It has no solution.
It has one solution.
It has two solutions.
It has infinitely many solutions.
OpenStudy (anonymous):
DO YOU KNOW HOW TO
OpenStudy (anonymous):
oops cap lock sorry
Mehek (mehek14):
\(\dfrac{3}{4z}-\dfrac{1}{4z+1}=\dfrac{2}{4z+1}\)
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Mehek (mehek14):
\(\dfrac{3}{4z}=\dfrac{3}{4z+1}\)
OpenStudy (anonymous):
i dont know how to do that :(
Mehek (mehek14):
\(\dfrac{4}{3}*\dfrac{3}{4z+1}\)
OpenStudy (anonymous):
what is z
OpenStudy (anonymous):
im sorry i am a very slow learner and horrible at math
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OpenStudy (anonymous):
can you explain more?
Mehek (mehek14):
hold on
OpenStudy (anonymous):
k
OpenStudy (anonymous):
Which statement is true about the equation fraction 3 over 4z − fraction 1 over 4z + 1 = fraction 2 over 4z + 1?
It has no solution.
It has one solution.
It has two solutions.
It has infinitely many solutions.
OpenStudy (anonymous):
lol i just wanna see it cuz the other one went up
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OpenStudy (anonymous):
it this question below
Which statement is true about the equation fraction 3 over 4z − fraction 1 over 4z + 1 = fraction 2 over 4z + 1?
It has no solution.
It has one solution.
It has two solutions.
It has infinitely many solutions.
Nnesha (nnesha):
\[\huge\rm \frac{ 3 }{ 4z } -\frac{ 1 }{4z+1 } = \frac{ 2 }{ 4z+1 }\] like this ?
OpenStudy (anonymous):
yeah but i dont get how to do that
Nnesha (nnesha):
first of all solve left side find common denominator
OpenStudy (anonymous):
4z + 4z
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Nnesha (nnesha):
when you multiply same bases you should add their exponents
so 4z times 4z= ?
OpenStudy (anonymous):
16z
Nnesha (nnesha):
common denominator is 4z(4z+1) so distribute parentheses by 4z
when u multiply same bases you should add exponents
\[\huge\rm x^m \times x^n = x^{m+n}\]
OpenStudy (anonymous):
wow i mind is BLOWN!!!
OpenStudy (anonymous):
i dont get it :(
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OpenStudy (anonymous):
im sry
Nnesha (nnesha):
4z times 4z =(4 times 4)(z times z)
Nnesha (nnesha):
z times z equal what ?
OpenStudy (anonymous):
16 and 2z
OpenStudy (anonymous):
z=8?
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Nnesha (nnesha):
nope add their exponents
z is same as z to the one power \[z^1 \times z^1 = z^{1+1}\]
OpenStudy (anonymous):
ok i dont get it im sorry
OpenStudy (anonymous):
if you dont want to help me thats okay cuz this will take a long time
Nnesha (nnesha):
here are examples \[\huge\rm x^2 \times x^2 = x^{2+2}\] \[\huge\rm 2^3 \times 2^3 = 2^{3+3}\] this is an exponent rule
when we multiply same bases we add their exponents
OpenStudy (anonymous):
ok
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