Question

If x-3 is a factor of P(x)=x^3-7x^2+15x-9
wouldn't (x-3)(x+4)(x+1) be the best representation for the complete factorization for P(x) ?

Answer 1

no I dont think so

Answer 2

So could you tell me what would be the best representation for the factorization of P(x)?

Answer 3

have you tried doing a polynomial long division?

Answer 4

Yes

Answer 5

Thats the answer I came up with

Answer 6

but when you expand the factors it doesnt bring you back to the original cubic.

Answer 7

when I divide the cubic by x-3 I get x^2-4x+3