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Mathematics 13 Online
OpenStudy (anonymous):

Plzz helpp! easy medal :) Factor x2 - 2x + 3.

OpenStudy (anonymous):

A. (x - 3)(x - 1) B. (x + 3)(x + 1) C. (x - 3)(x + 1) D. Prime

OpenStudy (anonymous):

I think the answer is D - Prime

OpenStudy (anonymous):

out of 10 how postive r u and can u explain plz why you think that @samchick1074

OpenStudy (anonymous):

@Hero can you come check my answer bro?

OpenStudy (anonymous):

^ hero

hero (hero):

What was your "answer"?

OpenStudy (anonymous):

D is that right

hero (hero):

@Calvin3, can you please explain how you arrived at D as your answer?

OpenStudy (anonymous):

as you can see up there Sam chick thinks it's D but I wasn't sure if he was right so, from the way you asked me i'm taking it that D is wrong and my answer is C am I right? @Hero

hero (hero):

So basically, you admit that you did not use any strategy to come up with D, which means you're essentially guessing, which is okay because we've all guessed at one point or another.

hero (hero):

But, here's a bit of information that can help you out: For a polynomial of the form \(ax^2 + bx + c\), the expression is factorable if \(b^2 = 4ac\) is a perfect square. Otherwise, it is prime.

hero (hero):

So, basically, your first step is to figure out whether \(b^2 - 4ac\) is factorable first before doing anything else.

hero (hero):

Sorry \(b^2 - 4ac\) not \(b^2 = 4ac\)

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