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a − 3b = 4 a = b − 2 What is the solution to the set of equations in the form (a, b)?
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(−2, −2) (−3, −1) (−9, −7) (−5, −3)
Use the substituion method plug in equation 2 into equation one \[\huge~\rm~ b-2 − 3b = 4\]
Now solve for b
wait how do I solve for b
Start by combining like terms
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b−2−3b=4 -3+1=?
-2
Good now we have -2b now we add 2 to both sides 4+2=?
6
So now we have -2b=6 Whats 6/-2 ?
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8
?
no wait u divide those right?
Yes
/=divide
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so than it would be -3
Yes now we plug -3 in place of b in equation 2 a=-3-2 -3-2=?
-5
good so we have b=-3 a=-5 whats the answer?
it would be D
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Good job! :D
thx for the help i'll fan and metal now ^_^
thanks ^.^
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