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Mathematics 17 Online
OpenStudy (anonymous):

Help me check my answer? Factor completely: 3x3 + 3x2 - 18x (4 points) 3x(x + 3)(x + 2) 3x(x + 3)(x - 2) *3x(x - 3)(x + 2) 3x(x - 3)(x - 2)

OpenStudy (freckles):

So first we notice that all three terms of that given polynomial have a common factor.

OpenStudy (freckles):

3x^3 is the same as 3x*x^2 3x^2 is the same as 3x*x -18x is the same as 3x*(-6) so we see the common factor is ?

Mehek (mehek14):

@kinserkara did you choose the third one? because it has a * by it

OpenStudy (freckles):

well your choices basically tell you the common factor is 3x but that leaves the x^2+x-6 to factor

OpenStudy (freckles):

do you know which two factors of -6 have product -6 and also add up to be 1?

OpenStudy (anonymous):

3x(x^2 - x -6) Then, factor the trinomial into a product of two binomials. 3x(x -3)(x+2)

OpenStudy (anonymous):

i was wrong?

OpenStudy (freckles):

well just a little bit you chose the number -3 and 2 but -3+2=-1 which isn't 1 you almost got it; just switch the negative around

OpenStudy (freckles):

you know that 3+(-2)=1

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

B?

OpenStudy (freckles):

yea

OpenStudy (anonymous):

ok thx

OpenStudy (freckles):

I'm still going to give @Cgsmith a medal because he did show how to factor x^2-x-6 which is (x-3)(x+2)

OpenStudy (anonymous):

yeah i wish i could give more than ne medal

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