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Domain and range of f(x)=1/x+1?
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First find all the values x CANNOT be...
the denominator \(\ne0\), correct?
so the eliminated value (otherwise known as the "restriction") is the value of x that makes the denominator \(=0\).
sooo the domain is 0 or no?
the domain of the function, is all x-values for which the function is defined. (all x-values that you can plug in into the function, without getting an undefined output) there is only 1 x-value that will give you an undefined output. this x-value is the value that makes the denominator=0 (the denominator is the "x+1" peace)
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so set the denominator=0, and solve for x, to find that one value that is not in your domain
oh okay. Thanks
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