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If y = 3x3 – 2x and dx/dt equals 3, find dy/dt when x = –2. Give only the numerical answer. For example, if dy, dt = 4, type only 4.
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so y = 9 - 2x?
how did you get that
Sorry, I'm asking you to clarify, what do you mean by "y = 3x3 – 2x" is that 3 multiplied by 3 or is that 3 times x to the power 3?
3x^3-2x
sorry my fault
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no problem, well dy/dt = (dy/dx)*(dx/dt) (chain rule) then dy/dx = 9 x^2 - 2 we already know dx/dt = 3 therefore dy/dt = 3*(9x^2 -2) so dy/dt = 27x^2 - 6
oh and then x = -2 so you get 102 i think
Okay i had to implicitly differentiate i forgot. Thank you so much!
np
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