Question

Did i do this right? here is my problem
(x – 2) (3x-4)
Remove the parenthesis x times 3=3x^2.
x times -4 = -4x
-2* 3x^2 = -6x^2 -2* -4x= 8x
Now we have -6x^2 -8x Not sure if i combine or Divide... Guessing i'll combine.
-6x^2 +-8x = 14^3 <-- my answer.

Answer 1

not quite, let's take it from the top

(x-2)(3x-4)

let's multiply the first terms

x*3x = 3x^2

then the outer terms

x*(-4) = -4x

then the inner terms

(-2)*(3x) = -6x

then the last

(-2)*(-4) = 8

now we combine:

3x^2 - 4x - 6x + 8 =

3x^2 - 10x + 8

Answer 2

let me know if there's anything you're still confused about

Answer 3

\(\large (x - 2) (3x-4)\implies
\begin{array}{crllll}
x\cdot 3x\implies &3x^2\\
x\cdot -4\implies &-4x\\
-2\cdot 3x\implies &-6x\\
-2\cdot -4\implies &+8
\end{array}\)

Answer 4

Where did the 3x^2 come from didn't we just use that to make 6x? @Vocaloid

Answer 5

you need to use the (3x) twice

Answer 6

(A-B)(C-D) = A*C-A*D-B*C+B*D

Answer 7

Wow didn't know that one.

Answer 8

maybe I can draw this one out?