Question

Jason has two bags with 6 tiles each. The tiles in each bag are shown below:

Make 6 squares. The squares are numbered sequentially from 1 to 6.

Without looking, Jason draws a tile from the first bag and then a tile from the second bag. What is the probability of Jason drawing the tile numbered 5 from the first bag and an odd tile from the second bag?

Answer 1

let's break the problem down into smaller pieces

1. what is the probability of drawing a tile numbered 5 from the first bag?

Answer 2

1/6

Answer 3

right! now let's move to the next part

2. what is the probability of drawing an odd tile from the bag?

Answer 4

1/2

Answer 5

right! now multiply the two probabilities together

(1/6)*(1/2) = ?

Answer 6

3/6

Answer 7

uh, not quite, we need to multiply them together

2*6 = ?

Answer 8

12/36

Answer 9

im so confused

Answer 10

not quite, all you need to do is multiply the numerators, then multiply the denominators

hint:

(A/B)*(C/D) = A*C/(B*D)

Answer 11

3/36