MEDAL AND FAN!!!!! PLEASE HELP!!!!!
Referring to the figure, find the probability that a point A, selected randomly on line NT, is on the given segment RU.
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OpenStudy (anonymous):
Please help
OpenStudy (anonymous):
@Zedditup Can you help please?
OpenStudy (anonymous):
Ohh this is not my strong point. @team_cuban you wanna handle this?
OpenStudy (anonymous):
Probability is not mine either lemme see.... @ganeshie8 @Hero @dan815
OpenStudy (anonymous):
@Vocaloid Please help
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Vocaloid (vocaloid):
probability = (length of RU)/(length of NT)
OpenStudy (anonymous):
How do I figure it out? @Vocaloid
OpenStudy (anonymous):
Right now I'm utterly confused
Vocaloid (vocaloid):
what is the distance between R and U?
OpenStudy (anonymous):
10-14 I guess
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Vocaloid (vocaloid):
distance is positive, so 14-10 = 4
now find the distance between N and T
OpenStudy (anonymous):
20-0
Vocaloid (vocaloid):
which equals...?
OpenStudy (anonymous):
20
Vocaloid (vocaloid):
right, now we can go back to our original equation
probability = (length of RU)/(length of NT) = ?
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OpenStudy (anonymous):
(4)(20)=80
OpenStudy (anonymous):
Right?
Vocaloid (vocaloid):
/ means divide
4/20 = ?
OpenStudy (anonymous):
You're right lol. My bad. so 4/20 or 20/4
Vocaloid (vocaloid):
4/20...
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OpenStudy (anonymous):
4/20 is .2
Vocaloid (vocaloid):
right, depending on how they want the answer, you can put in 0.2 or 20%
OpenStudy (anonymous):
Thanks for you help. Can I do 19 on my own and you tell me if I got it right or wrong?
OpenStudy (anonymous):
NT..... 20-0=20
HF..... 18-4=14
14/20=.7
OpenStudy (anonymous):
@Vocaloid So 70%?
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