Mathematics
7 Online
OpenStudy (anonymous):
Rewrite f(x) = 2(x − 1)2 + 3 from vertex form to standard form.
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OpenStudy (anonymous):
@dan815
OpenStudy (anonymous):
@TheSmartOne
OpenStudy (anonymous):
actually this is the new question
OpenStudy (anonymous):
Rewrite f(x) = 3(x − 2)2 + 1 from vertex form to standard form.
OpenStudy (anonymous):
@fred7
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OpenStudy (anonymous):
thank you so much the smartone
OpenStudy (anonymous):
(1,3) is your vertex
OpenStudy (anonymous):
wait so how does that help me
OpenStudy (anonymous):
Ok
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OpenStudy (anonymous):
This is in General form\[2(x-1)^2+3\]
OpenStudy (anonymous):
aight
OpenStudy (anonymous):
It is easy to find the vertex in general form , by equaling (x-1)=0
OpenStudy (anonymous):
wait which one is this the first or second one cause i dont need the first one any more
OpenStudy (anonymous):
From that you get (1,y)
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OpenStudy (anonymous):
Now you need to find the y value
OpenStudy (anonymous):
okay
OpenStudy (anonymous):
The y value is always the constant
OpenStudy (anonymous):
so tell whats the constant
OpenStudy (anonymous):
@braaaahhh
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OpenStudy (anonymous):
srry um im still lost is this the first or second question
OpenStudy (anonymous):
wats a constant @fred7
OpenStudy (anonymous):
A constant is a number that does not very due to a variable. The constant in 3x+9=y is 9,because it does not have a variable
OpenStudy (anonymous):
so the constant for two would be three
OpenStudy (anonymous):
@fred7
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OpenStudy (anonymous):
YA
OpenStudy (anonymous):
sO THEN (1,y) when why is the constant so whats the vertex
OpenStudy (anonymous):
So then the vertex is (1,3)
OpenStudy (anonymous):
You got X from (x-1)=0 and you got Y by finding the constant. Do you get it now
OpenStudy (anonymous):
Yes tahnk i got the answer on the test right thank you