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\[\lim_{x \rightarrow 2}(\sqrt{x+2}-\sqrt{2x})\div(x^2-2x)\]
@phi
direct substitution gives 0/0 i would apply l'hopitals rule
I haven't learned about that
this week we just learned about intro to limits
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one thought is to multiply top and bottom by \( \sqrt{x+2}+ \sqrt{2x} \)
ok so we need to find different way
let me multiply it
the top is a difference of squares
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