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OpenStudy (anonymous):
Solve the system algebraically. Check your work.
5x + 2y = 10
3x + 2y = 6
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OpenStudy (arindameducationusc):
i m here
OpenStudy (anonymous):
x=2 y=0
OpenStudy (usukidoll):
the y's seems to be the same
so we can distribute a negative sign all over one equation and use elimination method to solve for x.
OpenStudy (usukidoll):
@saseal please don't give direct answers as it's a violation of OpenStudy's Code of Conduct.
OpenStudy (anonymous):
oh ok..
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OpenStudy (anonymous):
Try using matrix method. It works everytime.
OpenStudy (arindameducationusc):
Check this
OpenStudy (usukidoll):
for some reason matrix method is taught way later :(
OpenStudy (anonymous):
Yea, they are saving the best for the last lol.
OpenStudy (arindameducationusc):
x John can find out now, what say guys?
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OpenStudy (usukidoll):
?
OpenStudy (arindameducationusc):
Y is in the solution I gave, now x he can easily find out by putting in the equation
OpenStudy (arindameducationusc):
OpenStudy (usukidoll):
oh XD
OpenStudy (anonymous):
\[A=\left[\begin{matrix}5 & 2 \\ 3 & 2\end{matrix}\right]\]
\[B = \left(\begin{matrix}x \\ y\end{matrix}\right)\]
\[C = \left(\begin{matrix}10 \\ 6\end{matrix}\right)\]
\[A ^{-1} = \left[\begin{matrix}0.5 & -0.5 \\ -0.75 & 1.25\end{matrix}\right]\]
\[A ^{-1}C = B = \left[\begin{matrix}0.5 & -0.5 \\ -0.75 & 1.25\end{matrix}\right] \left(\begin{matrix}10 \\ 6\end{matrix}\right) = Find out yourself :)\]
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