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HELP PLEASE Solve for x: 5x2 + 25x = 0 (2 points) x = 0, x = 5 x = 0, x = -5 x = -5, x = 0, x = 5 x = 5, x = 25
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5x^2+25x=0 is this the question?
yes
very easy.....
just take out common x
then equate x=0 and 5x+25=0
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got?
okay, o it is X=0, X=5
no x=-5
oh okay
is it bc we are subtracting 5?
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\[5x^2 + 25x = 0\\5x.x+5.5.x=0\\5x(x+5)=0\\ \implies\ either\ 5x=0\ or\ (x+5)=0\\ \implies\ either\ x=0\ or\ x=-5\\\]
when we shift 25 to the other side it becomes -25....
okay
follow @eninone steps its right....
anyone you can do....
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but there is only X=5 and X=25
never mind i know now
Ok....
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