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OpenStudy (anonymous):
Hey just wanting to know how you can find a parabola given the focal and directrix
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OpenStudy (anonymous):
Meant the equation of a parabola
OpenStudy (anonymous):
Sorry i don't know the question but i just wanted to say Battle Field Friends
OpenStudy (anonymous):
The vertex is half way between the Focal and the directrix
OpenStudy (anonymous):
\[y^2=4px\]
OpenStudy (anonymous):
Yes I know and so then I just plug in the numbers then?
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OpenStudy (anonymous):
parabola takes the from of \( y^2 = 4ax \)
OpenStudy (anonymous):
So then how would I solve it?
OpenStudy (anonymous):
The distance between directix and focus is 2p
OpenStudy (anonymous):
I will step out and let saseal take over so you do not get confused.
OpenStudy (anonymous):
Because I need to know how to find the equation first
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OpenStudy (anonymous):
Because I need to know how to find the equation first
OpenStudy (anonymous):
distance equation?
OpenStudy (anonymous):
Yes but is that it?
OpenStudy (anonymous):
Yes but is that it?
OpenStudy (anonymous):
you take the midpoint between focus and directix
\[(\frac{ x _{2}-x _{1} }{ 2 })\]
change it to y if your parabola opens the other side
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OpenStudy (anonymous):
yup that distance is your p and you plug it into the formula
OpenStudy (anonymous):
Soo is that it?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
Alright thank you!
OpenStudy (anonymous):
welcome
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