Question

Help !!!
Write an equation of a line that passes through the point (3, 2) and is parallel to the line y = 3x - 4

y = 3x + 7

y = 3x - 7

y =1/3 x + 2

y =1/3 x - 2

Answer 1

Use the point slop form and then convert it to y-intercep form

Answer 2

so y=mx+b . but i dont know which letters go with the numbers

Answer 3

Point slope form = \( \huge y – y_1 = m(x – x_1)\)

Put the point (3, 2) into that equation.


\( \huge y – y_1 = m(x – x_1)\)

\( \huge y – 2 = m(x – 3)\)

Since we know it is going to be parallel, we know that it is going to have the same slope of y = 3x - 4. The slope is 3 so we have

\( \huge y – 2 = 3(x – 3)\)

Now transfor this \( \huge y – 2 = 3(x – 3)\) into y-intercept form y = mx + b Can you finish ?

Answer 4

y-2= 3x+-3??
Im sorry im so confused

Answer 5

You are on the right track.

\( \huge y – 2 = 3(x – 3)\)

Now distribute the 3 in the ()
\( \huge y – 2 = 3(x – 3)\)

\( \huge y -2 = 3x - 9\)


Now add 2 to each side of the equation.

\( \huge y -2 + 2 = 3x -9 + 2 \)

Can you finish?.

Answer 6

y=3x-7

Answer 7

Correct!!!

Answer 8

Good job

Answer 9

So B

Answer 10

Yep!!!

Answer 11

Thank you soo much for helping me and being so patient

Answer 12

Anytime!!! That is what I am here for :-D

Answer 13

Thank you for learning and working hard!!!

Answer 14

Only thanks to you