Question

One questions! LAW OF SINES ALGEBRA 2

Answer 1

Answer choices:

A. 110. 0 degrees
B. 153. 9 degrees
c. 26.1 degrees
D. 70.0 degrees

Answer 2

lol very tricky

Answer 3

Can you help me?

Answer 4

it says use the law of sines to find angle B, but you cannot find angle B yet

Answer 5

oh

Answer 6

you want to use
\[\frac{\sin(B)}{b}=\frac{\sin(A)}{a}\] but you can't because you do not know \(b\)

Answer 7

what you really need to do is find angle C first
that you can do using the law of sines, since you know 3 out of the four numbers for the ratio needed

Answer 8

\[\frac{sin(C)}{19}=\frac{\sin(40)}{13}\] is where you have 3 out of the four numbers

Answer 9

so
\[\sin(C)=\frac{19\times \sin(40)}{13}\] making
\[C=\sin^{-1}\left(\frac{19\times \sin(40)}{13}\right)\]

Answer 10

obviously you need so use some kind of calculator for this
i can show you what i use

Answer 11

okay

Answer 12

http://www.wolframalpha.com/input/?i=arcsin%2819sin%2840%29%2F13%29

Answer 13

that is not your final answer of course, that is just C

Answer 14

okay

Answer 15

once you have \(C=69.69^\circ\) you can find \(A\)

Answer 16

you good from there?

Answer 17

Okay, how would I write the equation?

Answer 18

Not quite..

Answer 19

@satellite73

Answer 20

@triciaal pease help!

Answer 21

will you help me? @triciaal

Answer 22

you have two angles right?

Answer 23

the total is 180

Answer 24

\[180-40-69.96\]

Answer 25

oops
\[180-40-69.69\]

Answer 26

do you see that Angle C is 70?

Answer 27

Angles in a triangle add up to 180
40 + B + 70 = 180
solve for B

Answer 28

I tried to tag him but hedidn't come back

Answer 29

Yes, I see that angle C is 70

Answer 30

70

Answer 31

sorry I saw that after 2 tags together

Answer 32

is that all? It's just that equation?

Answer 33

that's what I got

Answer 34

okay, thank you for your help!

Answer 35

you are welcome