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Just out of curiosity, what do you guys get for this one?
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\[\frac{ x + 1 }{2 } + \frac{ x - 1 }{ 3 } = \frac{ 1 }{ 6 }\]
let lcm=6 \[\frac{ 3x+3+2x-2 }{ 6 }=\frac{ 1 }{ 6 }\]
\[\frac{ 5x+1 }{ 6 }=\frac{ 1 }{ 6 }\]
Do u need to solve for x??
Yes :) I have an answer, although it seems wrong. I'm curious to see what you guys get XD
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multiply both side of the equation by 6 we get \[5x+1=1\]\[5x=1-1\]\[5x=0\]\[x=0\]
did u got that?
Exactly, I made it x = 0, no matter how I went about it. Which just seemed wrong so I thought I'd get someone else's opinion.
ok
Thank you for your help :D
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