Question

Help On This LAST Algebra Problem Would Make My Week.

Answer 1

The function H(t) = −16t2 + 60t + 95 shows the height H(t), in feet, of a projectile after t seconds. A second object moves in the air along a path represented by g(t) = 20 + 38.7t, where g(t) is the height, in feet, of the object from the ground at time t seconds.

Part A: Create a table using integers 1 through 4 for the 2 functions. Between what 2 seconds is the solution to H(t) = g(t) located? How do you know? (6 points)

Part B: Explain what the solution from Part A means in the context of the problem. (4 points)

Answer 2

@jim_thompson5910

Answer 3

I'm working on the table

Answer 4

k

Answer 5

i don't think I'm doing it right, can you do the last two on your own while I do them? We check on each others.

Answer 6

well... try to do the table
see what you get... and post it, if you need to, just take a screenshot of it
or paste here

Answer 7

Time 1 2 3 4
H(t) 411 1239 2579 4431
g(t) 58.7 97.4 136.1 174.8

Answer 8

Not sure what I did wrong. I plugged in all the numbers and solved. @jim_thompson5910

Answer 9

Unless this is right https://nz.answers.yahoo.com/question/index?qid=20150728100650AAh5ZPo

Answer 10

@jdoe0001

Answer 11

I'm not getting those values

Answer 12

Hmmm... What should I do?

Answer 13

if t = 1, then

h(t) = -16t^2 + 60t + 95
h(1) = -16(1)^2 + 60(1) + 95
h(1) = -16(1) + 60(1) + 95
h(1) = -16 + 60 + 95
h(1) = 139

Answer 14

do the same for t = 2 through t = 4

Answer 15

Let's do the second part "Part B: Explain what the solution from Part A means in the context of the problem. (4 points)"

Answer 16

@jdoe0001 @jim_thompson5910

Answer 17

Part B: The solution for Part A has meaning in the context of the problem by showing how many seconds it would take for both objects to be at the same height.

Answer 18

Is that correct?

Answer 19

yes, I'd say so

Answer 20

yeah the point of intersection represents when h(t) = g(t) at the same time value t

Answer 21

your table for part A is off though

Answer 22

By alot?

Answer 23

look back at how I computed h(1)