The triangles are similar. Give the ratio of the perimeters and ratio of the areas of the areas of the first figure to the second.
^How do I solve this?

Question

The triangles are similar. Give the ratio of the perimeters and ratio of the areas of the areas of the first figure to the second. 
^How do I solve this?

campbell_st · Answer

well the the ratio of the areas is the square of the ratio of the perimeters

campbell_st · Answer

so f the perimeters are in the ratio 2:3

the areas will be in the ratio 4:9

so if the area of the 1st figure is 20   then  the area of the 2nd is 

(20/5)*9 = 36

hope it makes sense

-welp- · Answer

|dw:1438309389119:dw|

-welp- · Answer

I'm sorry, I don't understand.

-welp- · Answer

halp

campbell_st · Answer

so the ratio of the measurements is 32:28

which simplifies to 8:7

so the ratio of the areas is 

$$8^2:7^2$$

this is because the side length is a 1 dimension measurement and area is a 2 dimension measurement.