Question

Amelia rolls two fair number cubes numbered from 1 to 6. She first defines the sample space as shown below:

(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)
(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)
(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)
(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)

Based on the sample space, what is the probability of getting a total of 4?

6 over 36
5 over 36
4 over 36
3 over 36

Answer 1

@taramgrant0543664

Answer 2

So there are 36 options in total and we need to figure out which options are equal to four so
3+1
2+2
1+3
All equal 4 so there are three options so there is a 3/36 chance of rolling numbers that equal out to 4

Answer 3

I dont get it

Answer 4

OH WAIT I SEE

Answer 5

I'm assuming that when it says a total of 4 then the two numbers add up to 4