Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (anonymous):

.

OpenStudy (rhr12):

Help for what?

OpenStudy (anonymous):

@welshfella

OpenStudy (rhr12):

Easy prb. Hold on. Lemme take a look

OpenStudy (welshfella):

first you need to factor x^2 + 12x + 35 the factors will look like (x + a)(x + b) where a*b = 35 and a + b = 12 so can you work out the values of a and b are?

OpenStudy (welshfella):

factor 35

OpenStudy (anonymous):

7 and 5?

OpenStudy (welshfella):

right good now we need to factor the denominator

OpenStudy (rhr12):

X2+11/3 for the first one

OpenStudy (welshfella):

3x + 15

OpenStudy (anonymous):

what 3x +15?

OpenStudy (anonymous):

oh nevermind

OpenStudy (anonymous):

3(x+5)?

OpenStudy (welshfella):

3x + 15 factors to what?

OpenStudy (anonymous):

3(x+5)?

OpenStudy (welshfella):

right so we have (x + 5)( x + 7) ----------- 3 ( x + 5)

OpenStudy (anonymous):

so x+7/3 right?

OpenStudy (rhr12):

Get it?

OpenStudy (welshfella):

right

OpenStudy (anonymous):

@rhr12 i think you are wrong

OpenStudy (rhr12):

My bad. Its not possible

OpenStudy (anonymous):

@welshfella what about the next one?

OpenStudy (rhr12):

Sorry.

OpenStudy (welshfella):

No that is wrong rhrh12 you cannot divide those terms because the top and bottom are sums not products

OpenStudy (anonymous):

@welshfella what about the next one?

OpenStudy (anonymous):

isn't the next one b?

OpenStudy (welshfella):

that's easy factor 2x - 12 then simplify

OpenStudy (anonymous):

b?

OpenStudy (welshfella):

yes

OpenStudy (anonymous):

the third one?

OpenStudy (welshfella):

easy also factor 4x + 16

OpenStudy (anonymous):

4(x+4)

OpenStudy (welshfella):

right now simplify 4(x + 4) ------ 6

OpenStudy (anonymous):

not sure what i do next

OpenStudy (welshfella):

what is a common factor of 4 and 6?

OpenStudy (anonymous):

2

OpenStudy (anonymous):

isn't it B also?

OpenStudy (welshfella):

right so divide 4 and 6 by 2

OpenStudy (welshfella):

|dw:1438446007131:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!