Question

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Answer 1

www.tiger-algebra.com/drill/x~2-6x=-22/

Answer 2

kay thanks

Answer 3

mhm

Answer 4

Re arrange your equation a little bit
\[x^2-6x+22=0\]
your a times c is equal to 22, it's factors are 11 and 2, now you can't use 11 and 2 such that they add up to 6, because they are the only factors u can multiply to get 22,
so a different method must be used, do you know the quadratic formula??here it is for a quadratic equation of the form
\[ax^2+bx+c=0\]
\[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]

Answer 5

\[x^2-6+22=0\]\[x=\frac{ -6\pm \sqrt{6^2-4(1)(22)} }{ 2 }\]\[x=3+\sqrt{13}i \]\[x=3-\sqrt{13}i\]

Answer 6

you have a complex number here

Answer 7

so is that the answer?

Answer 8

depends on the context of your question, it can either be considered undefined or the complex number answer

Answer 9

i think it is the answer because it is a choice, so thank you!