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Mathematics 16 Online
OpenStudy (anonymous):

.

OpenStudy (anonymous):

OpenStudy (astrophysics):

Factor away

OpenStudy (astrophysics):

|dw:1438607790118:dw|

OpenStudy (astrophysics):

|dw:1438607800418:dw| first factor the red part, what do you get?

OpenStudy (astrophysics):

So the question you should be asking is how to factor

OpenStudy (astrophysics):

So for \[x^2+4x-5\] the way you can do this is, find two number that add up to 4 and multiply to give -5. So what are the two numbers?

OpenStudy (anonymous):

im not sure

OpenStudy (astrophysics):

-1 and 5, since -1+5 = 4, and -1 x 5 = -5...so we can write it as (x-1)(x+5) now you can try doing the other similarly or you can complete the square/ use quadratic formula \[ x = \frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\] this is the quadratic formula where your express is as such \[ax^2+bx+c\]

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