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Find angle A if DE is equal to 66 degrees and BC is equal to 23 degrees.
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|dw:1438614978271:dw|
But how do I solve for A?
sorry, the angle DCE is 33°, CDB is 23°/2, show the triangle ACD
the relation, DCE (external) is CDB + A
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use this formula :- |AE| |CE|=|AD| |BD|
angle A is 1/2 the difference between the two intercepted arcs. in other words \[ \angle A= \frac{1}{2}( \widehat{DE}- \widehat{BC})\]
A=4?
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