Question

We perform the experiment "Toss two dice". What is the probability of the event "no 3 appears on either face. answers 10/36 11/36 1/36 and 25/36

Answer 1

Do you know it

Answer 2

how many ways can you have no 3 on the first face?

Answer 3

For one die

Answer 4

1/6

Answer 5

there are 5 ways not to get a 3
should be 5/6

Answer 6

right

Answer 7

ok so 5/6

Answer 8

similarly, there is a 5/6 chance for the second die , not to get a 3

Answer 9

Now you multiply 5/6 * 5/6

Answer 10

31.36

Answer 11

no 25/36

Answer 12

in symbols
P( 1st die is not 3 & 2nd die is not 3) = P( 1st die is not 3) * P( 2nd die is not 3)

Answer 13

correct

Answer 14

because the events are indepenent

Answer 15

so that's the answer and thank you very much i m not good at math

Answer 16

your welcome

Answer 17

ok so if i roll a three i would do 3/6

Answer 18

I think this questions needs to state what numbers are on the dice before asking for the probability of no 3

if 3 isn't on the dice the the probability would be zero

Answer 19

thanks but i already got the answer srry