Lol i still can't get this halp 4(x + 1) = 4x + 4. 5 = 4 x 2 + 4 5 = 12
okay so i assume you just want to solve for x in the function 4(x + 1) = 4x + 4. right?
oops the 2 second lines are my work that i messed up on the problem is 4(x+1) = 4x + 4
Okay do you remember how to distribute the 4 into (x+1)?
the options for it are no solution 0 all real numbers 1
It's like taking 4 and multiplying x and +1 separately. Just think of it like that when you get started.
Did you get that @misty_fox?
4(x+1) = 4x + 4 we start of by distributing 4(x+1) = 4(x + 1) and here you can see that everything cancels out which usually means the solution is all real numbers to make sure you can plug in both 0 and 1 just to make sure and sure enough they both work
woops ment to say factoring not distributing but you can distribute too and you'd still get to equal functions on either side
Yes watchpencilpaper is right! :)
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