Question

Seth is using the figure shown below to prove Pythagorean Theorem using triangle similarity:

In the given triangle ABC, angle A is 90o and segment AD is perpendicular to segment BC.

Which of these could be a step to prove that BC^2 = AB^2 + AC^2?


By the cross product property, AB^2 = BC
multiplied by BD.

By the cross product property, AC^2 = BC multiplied by BD.

By the cross product property, AC^2 = BC multiplied by AD.

By the cross product property, AB^2 = BC multiplied by AD.

Answer 1

can anybody please help?

Answer 2

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