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Make [2(cos 15 + i sin 15)]^3 to the standard form a+bi
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\[[r (\cos(\theta)+i \sin(\theta)]^n \\ =r^n (\cos(n \cdot \theta)+i \sin(n \cdot \theta))\]
\[\text{ distribute } \\ =r^n \cos(n \theta)+ i r^n \sin(n \theta)\]
its called demoive's theorem I think
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