Question

find solutions between 0 and 2pi
7 sin2x - 14 sin x + 2 = -5
will fan and medal

Answer 1

so far i've subtracted 2 from each side and divided by 7 to get sin^2x-2sinx=1

Answer 2

@enchanted_bubbles @Peaches15

Answer 3

divided by 7 ?? why ?

Answer 4

this is like quadratic equation let sinx = x

Answer 5

\[\huge\rm 7x^2-14x+7=0\] now find GCF and then factor it
let sinx = x

Answer 6

to simplify the equation, because all three numbers where divisible by 7

Answer 7

oh

Answer 8

ohh right you mean GCF

Answer 9

i got x^2 -2x=0

Answer 10

http://www.wolframalpha.com/input/?i=7+sin2x+-+14+sin+x+%2B+2+%3D+-5

Answer 11

correct
so you will get \[\huge\rm \frac{ 7x^2 }{ 7}-\frac{ 14x }{ 7}+\frac{ 7 }{ 7 }=0\]

Answer 12

7/7 = ??

Answer 13

1

Answer 14

yes right so it's x^2 -2x +1 =0

Answer 15

OH right

Answer 16

after factor it ot
7(x^2-2x+1)=0 now set it equal to zero
\[7\cancel{=}0 ~~~~x^2-2x+1=0\]
now factor x^2-2x+1=0

Answer 17

ok gimme a sec

Answer 18

:=)

Answer 19

(x+2) (x-1)?

Answer 20

nope
2 times -1 = -2 but it suppose to be one
find two number when you multiply them you should get 1 and when you add or subtract them you should get -2

Answer 21

(x+2)(x-1)=0

Answer 22

ok

Answer 23

easy method to factor quadratic equation
find two number when you multiply them you should get product of AC and when you add or subtract them you should get middle term
a=leading coefficient
b=middle term
c=constant term

Answer 24

hang on a sec

Answer 25

(x-1)^2

Answer 26

?

Answer 27

yep right -1 times -1 = 1
-1-1=-2

Answer 28

now change it back to sinx
you get (sinx -1)^2=0 solve for sin x

Answer 29

I need to find the answers in between (0,2pi)

Answer 30

using the unit circle

Answer 31

yep so sinx -1= 0 solve for sinx
sinx =1 right ?
use unit circle to find radian where sinx = 1

Answer 32

ok that's what i thought thank you so much!

Answer 33

my pleasure!