Algebra
14 Online
OpenStudy (anonymous):
The pair of points is on the graph of an inverse variation. Find the missing value.
(2, 8) and (x, 3)
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OpenStudy (anonymous):
it can be 2, 16 5 1/3 or 12
OpenStudy (freckles):
well y varies inversely with x means
for constant k we have:
\[y=\frac{k}{x}\]
first step is to plug in (2,8) to find k
OpenStudy (anonymous):
ok
OpenStudy (freckles):
then after you find k
you can find x for when y is 3
OpenStudy (anonymous):
how would i find K?
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OpenStudy (freckles):
by pluggin (2,8) as suggested above
OpenStudy (anonymous):
ok. so y= 2,8/k?
OpenStudy (freckles):
(2,8) tells us when x=2 that y=8
OpenStudy (anonymous):
ok so 8 = K/2
OpenStudy (freckles):
solve for k or i guess you are calling it K
solve for K
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OpenStudy (anonymous):
how do i find k?
OpenStudy (freckles):
by solving 8=k/2
OpenStudy (anonymous):
so k =4?
OpenStudy (freckles):
notice you can just multiply both sides by 2
OpenStudy (freckles):
hmm 4/2 =8 is not true
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OpenStudy (anonymous):
so k is 2?
OpenStudy (freckles):
2/2=8 is not true
OpenStudy (anonymous):
16/2?
OpenStudy (freckles):
have you tried doing what I asked
multiply both sides by 2
OpenStudy (freckles):
8=k/2
multiply both sides by 2
2(8)=k
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OpenStudy (anonymous):
k=16
OpenStudy (freckles):
and as you see 16/2=8 is true
yes k=16
OpenStudy (freckles):
\[y=\frac{16}{x}\]
OpenStudy (freckles):
now the question is to find x for when y=3
OpenStudy (anonymous):
so the answer is B?
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OpenStudy (anonymous):
right?
OpenStudy (freckles):
have you found x for when y=3 yet?
OpenStudy (anonymous):
no...
OpenStudy (freckles):
well that is what the question ask you to do
OpenStudy (freckles):
it says to find x in the given ordered pair (x,3)
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OpenStudy (freckles):
(x,3) says what is x for when y=3
OpenStudy (anonymous):
ok (2,3)
OpenStudy (freckles):
you already found the equation above
OpenStudy (freckles):
you just need to input the y is 3
OpenStudy (freckles):
and solve for x
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OpenStudy (anonymous):
3= 16/8?
OpenStudy (freckles):
do you remember you found k was 16
so I replaced the k with 16 got you
\[y=\frac{16}{x}\]
re[place y with 3 and solve for x
OpenStudy (anonymous):
how do i solve X?
OpenStudy (freckles):
by solving the equation
3=16/x for x
OpenStudy (anonymous):
so that would be 5.3?
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OpenStudy (freckles):
close in decimal form that would be 5.33333333333333333333
but I think they wanted you to write it in mix fraction form not decimal form
OpenStudy (anonymous):
what would that be as a mix fraction?
OpenStudy (freckles):
so you never wrote improper fractions as mix fractions before?
OpenStudy (freckles):
16/3
3 goes into 16, 5 times with a remainder of 1
\[\frac{16}{3}=5\frac{1}{3} \]
OpenStudy (anonymous):
OHH
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OpenStudy (anonymous):
So the answer is D?
OpenStudy (freckles):
I don't know
whatever choice is 5 and 1/3
OpenStudy (anonymous):
ok