Question

how do i solve the equation by completing the square for x^2+6x=-8 with steps please

Answer 1

\(x^2+6x=-8\)
first, can you write it as:
\("something" \ = 0\)

Answer 2

where "something" has your various terms in it!

Answer 3

wait what

Answer 4

can you make the RHS of your equation equal to zero

Answer 5

what is that?

Answer 6

let's say i have :
\(x^2+4x=−10\)

i can then say that:
\(x^2+4x \ + 10=−10 \ + \ 10\)
\(x^2+4x + 10 = 0\)

then i am good to go


can tou do that with your equation?

Answer 7

okay thanks

Answer 8

wait what about the 4

Answer 9

what 4 ?

Answer 10

wait 6x i meant

Answer 11

OK, we can complete the square without fiddling around with your equation

so
\(x^2+6x=-8\)

look only at the L.H.S (left hand side):
\(x^2+6x= (x + A)^2 - B\)

Answer 12

wait is a and b the solution?

Answer 13

you will need A and B in the solution

tracking back, you asked : "how do i solve the equation by completing the square for x^2+6x=-8 with steps please "

that is a very reasonable question. do you know how to complete a square?

Answer 14

no lol i got a 15 percent on my test and can not get it for the life of me

Answer 15

crumbs :-(

what is \((x + 3)^2\)

can you evaluate that?

Answer 16

isit like (x+3) and (x-3)

Answer 17

crumbs almighty!!

am i actually helping you or hindering you?!?! i do wonder !!

\((x+3)^2 = (x+3)(x+3) = ....\)

Answer 18

both sorta

Answer 19

ok

love the directness!!

am i now defunct?

Answer 20

no sorry i was going somewhere

Answer 21

are we still going ???

Answer 22

wait so i would add 8 to -8 and it would make it zero?