Question

Zoe is using the figure shown below to prove Pythagorean Theorem using triangle similarity:

In the given triangle ABC, angle A is 90 degrees and segment AD is perpendicular to segment BC.

Which of these could be a step to prove that BC^2 = AB^2 + AC^2?
By distribution, AC^2 plus AB2 = BC multiplied by the quantity DC plus AB.
By distribution, AC^2 plus AB2 = BC multiplied by the quantity DC plus BD.
By distribution, AC^2 plus AD2 = BC multiplied by the quantity DC plus AB.
By distribution, AC^2 plus AD2 = BC multiplied by the quantity DC plus BD.

Answer 1

@OregonDuck @Hero @sammixboo @cicilynxox @Michele_Laino @Miracrown @iiAriana @BioHazard9064 @sugarplum15 @dan815 @DanJS @automaticloveletter

Answer 2

http://openstudy.com/study#/updates/4fbf9fede4b0964abc821e39

Answer 3

@Echosmith

Answer 4

No offense but I hate when people give me links. I read all links before I ask a question. If I ask the question that means I don't understand the explanation in the link. So please....

Answer 5

:| <---- my face rn

Answer 6

@princeharryyy @Prosper2win @PrinceKel @abb0t @veedotvee @Compassionate @nincompoop

Answer 7

@ganeshie8 @IrishBoy123 @taramgrant0543664

Answer 8

Good luck

Answer 9

Wdym good luck?

Answer 10

If you aren't going to help please do not spam my question @automaticloveletter

Answer 11

I just gave you good luck since I can't help you, that isn't spam.

Answer 12

i got it

Answer 13

What is it?

Answer 14

nvm, it was a diff prob my bad

Answer 15

@ganeshie8 we need help because this is confusing

Answer 16

Well I guessed and got it wrong. It is not D.

Answer 17

It is B

Answer 18

Would you like to know why?