what is the radius? x^2+y^2-2x+6y+9=0
\[\sqrt{9}=?\]
maybe it helps to rearrange this equation first and then have it in the equation of the circle format.
completing the square needs to be done for the x and y terms separately of course
OH right forgot that @freckles
oh yes.
the answer is 1 thank you all though :)
how did you get 1?
graphing calculator perhaps
or desmos/wolfram alpha XDDDDDDDDDDDDD
\[(x^2-2x)+(y^2+6y)=-9\]
i didnt but i got answer wrong and the test said the correct anwer was 1 lol
thats why we never get mcq for test
<_< yeah that's why I asked... you need to understand the concepts of this so you can be able to solve these equations
mcq? @saseal
multiple choice questions
oh XD. Come to think of it, it's been years since I had one
@grecar98 take that equation i gave ya and complete the square
time for me to learn bitumen road making...afk!
as the OP has found the answer: \(x^2+y^2-2x+6y+9=0\) rearrange \(x^2 - 2x +y^2+6y+9=0\) complete squares \([(x-1)^2 -1] +[(y +3)^2 - 9] +9=0\)
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