Help? I'm stuck. Applications of Quadratic Applications.

Question

yanasidlinskiy · Answer

$$S=-16t^2+11t$$
$$(-1)0= (-1)(-16t^2+112
t)$$
$$0=16t^2-112t$$
That is what I got. I've tried solving further but I'm confused...

hihi67 · Answer

what r u tryin to figure out

yanasidlinskiy · Answer

Well, now I'm supposed to be factoring the last equation...

anonymous · Answer

try completing the square

astrophysics · Answer

You could use the quadratic equation if you like, c = 0, or complete the square.

hihi67 · Answer

itll be in the form (a-b)(a+b)

yanasidlinskiy · Answer

Yes, I do know that I just do not know how to go from what I've put up last.

hihi67 · Answer

just take any random number, plug it in and see what happens i guess lol

astrophysics · Answer

You could just do (11-16t)t=0 that gives your factors

astrophysics · Answer

factoring out a t

yanasidlinskiy · Answer

Nevermind I got it haha. Thanks guys!

astrophysics · Answer

Ok :)

anonymous · Answer

$$16t^2-112t+(\frac{ 112 }{ 2 })^2= (\frac{ 112 }{ 2 })^2$$

anonymous · Answer

lol ok

astrophysics · Answer

S = -16t^2+11t is different from 16t^2-112t, I'm assuming there was just a mistake there, but you can do the same as above for it in any case, I guess you realized that :P