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Given f(x)=3x^2+18x+6 where is its vertex?
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formula to find x coordinate of vertex \[\huge\rm x=\frac{ -b }{ 2a }\] and then substitute x in f(x) function for x value to find y
a and b are \[\huge\rm Ax^2+Bx+C=0\] a=leading coefficient b=middle term
so just solve it first
yes right first find x-coordinate
21x?
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how did you get that ?
a= ?? b= ?
a=3x^2 b=18x
just the coefficient
so a=3 b=18 now use that formula that i posted bove
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-3
nvm yes
now to find y coordinate of vertex substitute all x in f(x) function for -3
so its -3, -21
yes right
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