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Mathematics 12 Online
OpenStudy (anonymous):

K

OpenStudy (anonymous):

@DanJS @NemesisFeeDz

OpenStudy (anonymous):

@welshfella @Yukina99 @undeadknight26 @IrishBoy123 @ParthKohli @satellite73 @ganeshie8

OpenStudy (anonymous):

0.0

OpenStudy (anonymous):

I honestly have no clue how to do this

OpenStudy (anonymous):

find the zeros by grouping the equation

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

what?

OpenStudy (anonymous):

nvm give me a min

OpenStudy (anonymous):

@Hero

undeadknight26 (undeadknight26):

*cough* B *cough*

OpenStudy (anonymous):

its b

OpenStudy (anonymous):

y?

OpenStudy (anonymous):

if you group the equation you end up with x^2 (x + 1) - 1 (x + 1) Make that (x + 1)(x^2 - 1) the zeros of x + 1 is -1 the zero of x^2 - 1 is 1

OpenStudy (anonymous):

ooh ok thank you!!

undeadknight26 (undeadknight26):

Who wonders why they changed the question to K?

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