Question

please help im so stuck Given the following functions f(x) and g(x), solve f over g (−5) and select the correct answer below:

f(x) = 2x − 20

g(x) = x − 1

Answer 1

f(-5) / g(-5)

that right?

Answer 2

-5 is one of the choices but im not sure

Answer 3

could you explain to me how you got that answer?

Answer 4

−5
5
one sixth
30
the coices

Answer 5

\[\frac{ f(-5) }{ g(-5) } = \frac{ 2(-5)-20 }{ -5 -1 }\]

Answer 6

right , yeah it is f(-5) / g(-5), just evaluate both and put them over each other

Answer 7

ok thank you can you help with few more just trying out openstudy for the first time my friends said it helps

Answer 8

yes, depends on who helps ya.. .. just ask a new thread

Answer 9

you mean like post the question by itself?

Answer 10

screw it, here is fine

Answer 11

ok 1 sec

Answer 12

given the functions f(x)and g(x), solve (f times g)(3) and select the correct answer below
f(x)4x^2+12
g(x)=x-1

Answer 13

f times g, or is it a small circle looking thing

Answer 14

47
-47
96
-96
are choices

Answer 15

its a small cirlce

Answer 16

ok, then it is a compound function f[g(x)]

Answer 17

so how would i set up the equation

Answer 18

nope, it is gonna be multiplication

Answer 19

f(3) * g(3) =

Answer 20

so i would multiply the 2 equation they gave me?

Answer 21

so
(4x^2+12)3 and (x-1)3?

Answer 22

you could do that first, or put in the value for x to start,

[4(3^2) + 12] * (3-1)

Answer 23

hows did you get the value of x

Answer 24

THe problem says [f times g ](3) , x=3

Answer 25

so you just evaluate both f and g at x=3 , then multiply the values together

Answer 26

ooo ok

Answer 27

let me try it

Answer 28

I have time for one more if you want

Answer 29

f(3) * g(3) = [4(3^2) + 12] * (3-1) = 96

Answer 30

how did u get 96 i got 168

Answer 31

[4*9 + 12]* 2

Answer 32

48*2

Answer 33

ok and wat a bout the part when you multiply it by 3-1

Answer 34

that is what happened, the 2 at the end...

f(3) * g(3) = [4(3^2) + 12] * (3-1) = 96

Answer 35

ook

Answer 36

i get it now i messed up omewhere but i see thay why its a 2 at the end cuz 3-1 is 2 ok can u hepl with one more?

Answer 37

yep

Answer 38

Given the following functions f(x) and g(x), solve f[g(6)] and select the correct answer below:

f(x) = 6x + 12

g(x) = x − 8

Answer 39

choices are −96
0
24
48

Answer 40

These compound functions like that, you work from the inside most function first, then outwards carrying the values...

Answer 41

figure out g(6), then use that value in f(x) for x

Answer 42

so x is 6?

Answer 43

yes, anytime you see g(#) or f(#) some number, that is what x is

Answer 44

k so now i plug it in dont tell me ill tell u n u tell if its right

Answer 45

So what is g(6)

Answer 46

is it -2?

Answer 47

no...

First , what is g(6) ?

Answer 48

i did x-8 and plugged 6 for x

Answer 49

right, so g(6) = 6 - 8 = -2

Answer 50

ok so now f

Answer 51

now you use that value you just got in the f function for x

Answer 52

f is 48?

Answer 53

f(-2)

Answer 54

6times 6 plus 12

Answer 55

no, that is the thing with the compound functions, you have to use the value from g(6) = -2
for the value of x in f(x)

Answer 56

Figure the inner function out, use that value in the next function

Answer 57

o ok so i plug the -2 in instead of the 6?

Answer 58

Yes..

f[g(6)] = f(-2)

Answer 59

can you explain how you get that from f(x)=6x+12?

Answer 60

ok, start over from the beginning...

Answer 61

ok

Answer 62

f [ g(6) ]

What that means is instead of having the usual f(x), you have f( another function)

Start with the inner function g(6) and evaluate. g(6) = -2

Now you can replace g(6) with -2 in the original problem

Answer 63

Left to evaluate f(-2)

Answer 64

oo ok

Answer 65

so where do i go from here?

Answer 66

just left to evaluate f(-2) = 6*(-2) + 12

Answer 67

o ok so now u added the 6(-2)+12 wouldnt it be 0

Answer 68

so it is zero

i have to take off, you can fan me , ill prolly be on later

Answer 69

ok how do i fan you?

Answer 70

nvm n did it thanks