Given f(x) = 4x + 13 and g(x) = 10x − 2, solve for (f + g)(x) and select the correct answer below. (f + g)(x) = 14x + 15 (f + g)(x) = 14x + 11 (f + g)(x) = 6x + 11 (f + g)(x) = 6x + 15
@Vocaloid
add both function f(x)+g(x)
how would i do that just add f(x) + f(x)
f(x) and g(x) what is f(x) equal to ? and what is g(x) equal to ?
\[\huge\rm \color{reD}{f(x)}+\color{blue}{g(x)}\] f(x) =4x+13 g(x)=10x-2 so replace f(x) and g(x) for 4x+13 and 10x-2 \[\huge\rm \color{reD}{(4x-13)}+\color{blue}{(10x-2)}\] combine like terms
14x-15 @Nnesha sorry internet connection hapned :/
how did you get -15 ?
k here is my work: 4x + -13 + 10x + -2 4x+ -13 + 10x + -2 = (4x + 10x) + ( -13 + -2) = 14x + -15 Answer is : 14x -15
it's not -13 13 is positive
I'm not sure i have a math website that a trust and 14x-15 came up with it its called mathway
you don't need a calculator for this one and i'm pretty sure u pluggedin wrong thing
you did ask 4x - 13 so it actually is negative i am not trying to debate with you but i am jus trying to make sure that we are on the same page lol
nvm i typed it wrong
well it's 4x+13 in the question i'm stupid but you should pay attention :=)
\(\color{blue}{\text{Originally Posted by}}\) @Nnesha \[\huge\rm \color{reD}{f(x)}+\color{blue}{g(x)}\] f(x) =4x+13 g(x)=10x-2 so replace f(x) and g(x) for 4x+13 and 10x-2 \[\huge\rm \color{reD}{(4x-13)}+\color{blue}{(10x-2)}\] combine like terms \(\color{blue}{\text{End of Quote}}\) correction: \[\huge\rm \color{reD}{(4x+13)}+\color{blue}{(10x-2)}\]
ok lol well i will do that now : D
14x+11 i believe @Nnesha
right
ty may you help with one more please an thank you lol @Nnesha
whats funny ?? :o and sorry i have to go.
that ok :0
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