Algebra
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OpenStudy (kaylaprincess):
solving radical equation please check my answer?
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OpenStudy (kaylaprincess):
why wouldn't it be x = 5, not extraneous ?
Nnesha (nnesha):
show your work.plz
OpenStudy (kaylaprincess):
i know, I should've subtracted five, and then square booth sides
Nnesha (nnesha):
wrong.
OpenStudy (kaylaprincess):
I had just gone straight to squaring the whole equation?
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Nnesha (nnesha):
5 is under the square root so you can't move it to the right without removing square root
OpenStudy (kaylaprincess):
then subtract?
OpenStudy (kaylaprincess):
lemme resolve
OpenStudy (kaylaprincess):
do you still want a picture of my work?
Nnesha (nnesha):
yep
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OpenStudy (kaylaprincess):
this is how i got the x = 5, not extraneous
OpenStudy (kaylaprincess):
re solving atm
OpenStudy (kaylaprincess):
but i did square first there ^
Nnesha (nnesha):
well well well.
first step is to divide both side by 2
Nnesha (nnesha):
then take square root both sides
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OpenStudy (kaylaprincess):
cause of the two infront of the radical?
Nnesha (nnesha):
yep right you need to transfer all numbers that is outside the radical sign to the right side
that's always going to be First step
Nnesha (nnesha):
to take square root you need just radical sign at left side
OpenStudy (kaylaprincess):
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