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Factor the GCF: 21x3y4 + 15x2y2 − 12xy3.
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what is th elargest number that can divide evenly into 21, 15, 12
@Hayden123Pierce
going off of what Dan said, the GCF is 3 since it can be divided by 21,15,and 12 evenly.
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ok
yes, so pull a 3 out from each term
for the variables, it will be the smallest power as long as every term has that variable in it
Every term has an X and a Y^2
so overall, take out 3*x*y^2
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He's right:)
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