Question

Factor completely: 6x^2-4x-2

Answer 1

take a 2 out first.

2*(3x^2 - 2x - 1)

Answer 2

okay i did that, then i did 2(3x-3x)(x-1)

Answer 3

you have factors

3 1 --- 1 1

you need to make a -2 out of that , so +3 and -1

Answer 4

explain i dont get it

Answer 5

Here you can put in the x terms since 3 and 1 are the only choice

2*(3x )*(x )

Answer 6

and the other choice is only 1 and 1 for the others, you just have to decide the sign in each one + or -

Answer 7

2*(3x 1 )*(x 1)

Answer 8

put in the + or - , so that when you distribute that, you get a -2 on the X term

Answer 9

i already put the x terms in as 2(3x-3x)(x-1)

Answer 10

what do i do next

Answer 11

2*(3x^2 - 2x - 1)
= 2( 3x^2 - 3x + x - 1)

now factor the expression in the parentheses by grouping

Answer 12

first factor 3x^2 - 3x
- take 3x out

Answer 13

so add 3 to both sides?