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2e^2x-3=8 solve:
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add 3 divide by 2 take the log divide by 2 again
ill try
nvm it was answered
still dont quite understand what to do with the log
\[e^{\xi}=A\\ \xi =\ln(A)\]
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so when you get to \[e^{2x}=\frac{11}{2}\] the next step is \[2x=\ln(\frac{11}{2})\]
okay, thats what i did i just wasnt sure if it was right, thank you
yw
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